Convert DNA string to binary
Getting fed up with writing this, so here’s some basic code to do it:
#include <iostream>
using namespace std;
uint32_t dna_number(string s) {
uint32_t num = 0;
for(size_t n=0;n<s.size();n++) {
num = num << 2;
if(s[n] == 'A') num += 0;
if(s[n] == 'C') num += 1;
if(s[n] == 'G') num += 2;
if(s[n] == 'T') num += 3;
}
return num;
}
int main(int argc,char **argv) {
cout << dna_number("AAAAA") << endl;
cout << dna_number("AAAAC") << endl;
cout << dna_number("AAAAG") << endl;
cout << dna_number("AAAAT") << endl;
cout << dna_number("AAACA") << endl;
cout << dna_number("AAACC") << endl;
cout << dna_number("AAACG") << endl;
cout << dna_number("AAACT") << endl;
cout << dna_number("AAAGA") << endl;
cout << dna_number("AAAGC") << endl;
cout << dna_number("AAAGG") << endl;
cout << dna_number("AAAGT") << endl;
cout << dna_number("AAATA") << endl;
cout << dna_number("AAATC") << endl;
cout << dna_number("AAATG") << endl;
cout << dna_number("AAATT") << endl;
cout << dna_number("AACAA") << endl;
}
RSS
What if my string is > 32 bits? if it is shorter than 32 than won’t it accidentally add extra As in the beginning of the sequence?
What if my string is > 32 bits? if it is shorter than 32 than won’t it accidentally add extra As in the beginning of the sequence?
eg. AAAAAAAATTTTTTTT == TTTTTTTT?
will u pl z tell me the code for converting binary to dna